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When will IGCSE results be out? Usually results will be released in August for June series, and in January for
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11,220 responses
BTW duys… i remember sm1 asking for some help in computer science… so try this site… i hope this is helpful IF u aren’t already done..
https://iteach.pk/category/course/igcse/0478-computer-science/
sorry… dint get copied earlier… 😐
its kk thank u………
Yea that was me. What site?
I don’t c anything
which site? you didnt link
hello saibi khan……..
i cannot see the website u put for computer science……..plz can u resend the website for computer science u put ealier
plzzzzzz
sorry guys… it dint get copied earlier its there now i guess…. sorry again…
Does anyone remember what were the 4th and 5th questions in chemistry paper 32?
Who’d want to remember that paper? Just wait till next year and probably, it’d be out by then.
nice reply 😛
excellent Philips
love ur idea!
DEAR IGCSE CENTRE TEAM,
can i get a good and simple website where i can learn physics for paper 3
our teacher has not helped us much in the syllabus……..
our teacher has only tought us the core syllabus and i take extended………can u plz help me out…….
Hello Taniya,
Some of our lovely readers here share this with you:
https://www.wiziq.com/tutorial/455200-IGCSE-PHYSICS-REVISION-NOTES
Ps. would also need help
GUYS!!!!!!!!!!!!!!!!!!! PLEASE HELP ME OUT!!!!!!!!!!! I’M SOOOO PISSED AND I DON’T FEEL LIKE STU”DYING” ANY MORE!!!!!!!!!!!!!!!!! I DON’T EVEN GET A SINGLE THING IN PHYSICS!!!!!!!!!!!!!!!!!!!!!!
Lol don’t stress. Take a break, read a book or watch some tv (just a few minutes, mind you :P). It will be a bit easier to get back to studying then. And try reading over classnotes, they are usually more concise than textbooks.
I have wonderful resources , try emailing me … @
hamoozy_adwan2020@hotmail.com
email about the whole of physics??? 🙁
Focus on past papers and look at the mark scheme. Best option for last second revision. Helped in Math p4
thanks guys!!!!!!!!
u all r the best
how weird it is… we dont even know eachother but we tend to help… what if personally knew sm1 and that sm1 hates me in real lyf but here cuz i have my nick name they wudn’t know who i am keep helping!!! 😛
exactly 2 posts up i was saying that i love how u guys help out blindly
faith in humanity restored!
hehehe i guess we think just so similarly!! 😛
hey…….any easy physics notes for pper 3……plzzzzz
check down where whoelse asked them
hey guys!!!!!!!!!!!! I’m sooooooooooooo happpppyyyyyyyyyyyyyyy!!!!!!!!! i have only ONE day left wbu guys!!!!!!!??????????? who else joins me for tomorrow???????????!!!!!!!!!!!
same. ive only got physics for tommorrow and then im free!
yayayay I do! :’D
Which country are you from? I live in KSA :3
it was a long wait :\
same here in jeddah!!!!!!! 😉
ME 😀
Me too! But I have NO tolerance to study AT ALL.
agree!!!!!!
I sort of do. I have history paper 2 later on June 1st
saibi u went insane these 2 days posting every where
hahaha
can someone smart explain terminal velocity and its link to acceleration and forces? 🙂 thanks in advance
Terminal velocity is when something is free-falling (propelled downwards by gravity),
the drag/air resistance equals acceleration due to gravity,this means that there will be no overall net force, meaning the object will fall downwards with a constant velocity.
Tell me if i’m wrong 😛
Bad at physics 🙂
Acceleration due to gravity causes you to fall down and your velocity increases. However there is air which pushes you up against gravity – air resistance. Air resistance is proportional to velocity; the faster you go the more you are pushed in the opposite direction.
Acceleration remains constant (negligibly increases), but velocity is still increasing which means air resistance is still increasing. There comes a point when air resistance equals acceleration thus the net force on the body is zero. The body continues to fall at that constant velocity.
Hope this explanation is sufficient. Good Luck!
If there is a parachutist free falling
1) he will fall with constant acceleration which is acceleration of free fall 10m per second square,
2)air resistance will increase to balance the body and so acceleration will start decreasing which means that “he is still speeding up yet with a decreasing rate”
3) air resistance equals the weight of the body so acceleration reached zero resultant force equals zero and therefore body is falling with terminal velocity “constant speed”
That’s it if its just a body free falling, but if it’s a parachutist:
4)opens parachute so area exposed to air resistance increase so person starts deceleration “rate of speed decreasing ” and air resistance gets greater
5) forces again gets balanced at a highly reduced terminal velocity
Terminal velocity is the highest velocity attainable by an object as it falls through air. It occurs once the sum of the drag force (Fd) and buoyancy equals the downward force of gravity (FG) acting on the object. Since the net force on the object is zero, the object has zero acceleration. [1]
In fluid dynamics, an object is moving at its terminal velocity if its speed is constant due to the restraining force exerted by the fluid through which it is moving.
As the speed of an object increases, the drag force acting on the object, resultant of the substance (e.g., air or water) it is passing through, increases. At some speed, the drag or force of resistance will equal the gravitational pull on the object (buoyancy is considered below). At this point the object ceases to accelerate and continues falling at a constant speed called terminal velocity (also called settling velocity). An object moving downward with greater than terminal velocity (for example because it was thrown downwards or it fell from a thinner part of the atmosphere or it changed shape) will slow down until it reaches terminal velocity. Drag depends on the projected area, and this is why objects with a large projected area relative to mass, such as parachutes, have a lower terminal velocity than objects with a small projected area relative to mass, such as bullets.
Terminal velocity is the maximum velocity an object can reach while falling. An object reaches terminal velocity when the air resistance is equal to acceleration or in other words the upward force is equal to the downward force.
I hope this is helpful.
ok so basically when an object is falling, it has a downwards force (gravity), right? Now with time, an opposing upwards force builds up (air resistance). Eventually the air resistance force equals the force of gravity. This means that the resultant force is 0. Ok so now using the formula F=ma, we can substitute F with 0. In order for F to be 0, a has to be 0 too (obviously the mass can’t be 0). This means that there is no acceleration. The object falls with a constant speed
Terminal velocity is the velocity of a falling object when it falls at a steady speed and all the forces acting on it are equal… acceleration is connected to it as if there isn’t any acceleration ( as we know acceleration of a free falling object is 10m/s^2 ) it means what ever weight of the object (Example coin and tissue) both fall on the same time at the same speed… and forces are connected because c’mon we know everything stationary OR moving has forces acting on it and terminal velocity is ONLY when all forces(air drag and weight etc.) are equal on the falling object hope this helps…. for more try this website….
https://www.passmyexams.co.uk/GCSE/physics/air-resistance-terminal-velocity.html
Hope this helps 🙂
Terminal velocity is the point where and object falls with a constant speed ( this doesn’t mean it’s accelerating ) it is where weight (graviton all force ) is equal to air resistance . Therefore net force would be ZERO , used the forumla F=ma , of net force was zero 0=ma then a(acceleration) =0
Terminal velocity is the point where speed is constant (so if you have a graph of speed against time, there would be a horizontal line). At this point, acceleration is equal to zero (and acceleration is equal to resultant force), so resultant force is as well equal to zero.
Terminal velocity is when weight=air resistance. The 2 balances equal each other out and so speed will remain constant. Important thing to remember is the resultant force =0, and speed is constant 🙂
When a body falls through air then the frictional force of air has an effect on the velocity of the body. Since frictional force is directly proportional to velocity, as the velocity increases due to the force of gravity, so does the frictional force acting against the body. As a result the object’s velocity accelerates at a decreasing rate. Eventually the frictional force becomes equal to the weight of the body and the net force becomes zero. Then the body moves at a constant velocity and this velocity is called terminal velocity
All I know is that terminal velocity is the highest speed an object obtains while it’s on free fall where upward force and drag force are equal to the downward force due to its mass. Donno the equation tho..
you guys for chem p31, question about the yeild increasin uder ice cold condition what can u say about the forward reaction? what did u write?
and the question about which position, A B C, last question, what did u write and why?
1- I said forward reaction is exothermic because it is favoured by low temperature thus producing bor ICl3 which is yellow in colour
2- C because Mr of HBr is 81 while the other compound was only 45 so It diffuses faster than HBr and so within the same time, HBr diffuses less than the other compound!
i wrote forward reaction is exothermic since a) bond forming is exothermic, and b) high temperatures decrease the yield of exothermic reactions so if low temperatures increase the yield, that must mean the reaction is exothermic 🙂
For the last question i chose C, because ethylamine had a lower value of relative molecular mass (45) whereas hydrogen bromide hada higher value (81) ethylamine would diffuse faster 🙂
Can’t really remember for the first one. But for the last I chose position C, because the HBr molecules were heavier, so would diffuse more slowly than the other one.
It was A because one of the gases will diffuse faster .
I wrote C because HBr is heavier in terms of relative molecular mass therefore it will diffuse slower.
C
Molecular mass of ethylamine is 45. Of HBr is 81, hence ethylamine can travel faster and diffuse at faster rate so white solid produced near HBr which is indicated by C
that it is exothermic and is favoured by low temp
C
A as the Mr of that compound was ”almost” double the Mr. of the CH3CHOOH (i’m not sure if this was the compound but its Mr was almost half of the other sub so we know that when an object is heavier, it moves slower sothe compound forms near the non-organic compound…
got it??? actually asking u cuz my structure isn’t perf but i know that the answer is right
sorrrryyyyyyyyyyyyy!!!!!!!!!!!!! it was C not A!!!!!!!!!!!!!!! sorrryyyyyyyyyyyyy again!!!!!!!!!!1
Decrease in temperature will favor the exothermic reaction (which they said was the forward reaction) so the yield will increase. 🙂
The forward reaction was exothermic. And it was c, we had to find the Mr.
the rxn was exothermic
Reaction is exothermic, because low temperatures favor exothermic reaction and more yiield produced.
the forward reaction is supported by cold temperatures showing that it is exothermic as only endothermic reactions require the heat energy and cooling removes heat making it an exothermic reaction…
I hope u get this but i think u might get confused because of my question structure 😛
i mean ANSWER structure**
no Saibi, it wasn’t A… it couldn’t have been because HBr was on the right side and it had a greater molar mass, so it diffused slowly and took more time than ethylamine…
OH THANKK GODDDD!!!!!
I WROTE THE EXACT SAME THING!!! *phew*
I said: exothermic because under high temperatures, it becomes a backward reaction, which is endothermic. so forward reaction is exothermic.
C, because the mr of HBr is smaller than that of the ethylamine (81>45) so it diffuses slower causing the white solid to form at C.